2v^2-17v+35=v-5

Solution for 2v^2-17v+35=v-5 equation:

2v^2-17v+35=v-5

We move all terms to the left:

2v^2-17v+35-(v-5)=0

We get rid of parentheses

2v^2-17v-v+5+35=0

We add all the numbers together, and all the variables

2v^2-18v+40=0

a = 2; b = -18; c = +40;
Δ = b2-4ac
Δ = -182-4·2·40
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2}{2*2}=\frac{16}{4}
=4
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2}{2*2}=\frac{20}{4}
=5
$